sql-server – 如何在一个查询中连接一列内连接中多行的字符串
发布时间:2021-03-19 08:07:57 所属栏目:MsSql教程 来源:网络整理
导读:我有一个查询结果如下: 查询: SELECT Tasks.TaskId,Comments.Comment,comments.timespent FROM commentsINNER JOIN tasks ON comments.entityid = tasks.taskid WHERE ( comments.entity = 1 ) GROUP BY Tasks.TaskId,comments.timespent 结果: TaskID Com
我有一个查询结果如下:
SELECT Tasks.TaskId,Comments.Comment,comments.timespent FROM comments INNER JOIN tasks ON comments.entityid = tasks.taskid WHERE ( comments.entity = 1 ) GROUP BY Tasks.TaskId,comments.timespent 结果: TaskID Comment TimeSpent __________________________ 111754 C1 4 111754 C2 1 111754 C3 79 请告诉我如何编写查询以获得如下结果: TaskID Comment TimeSpent __________________________________ 111754,C1,C2,C3 84 提前致谢. 解决方法这是工作的SQL小提琴: http://sqlfiddle.com/#!3/3597a/3这是实际工作的SQL. SELECT Tasks.TaskId,SUBSTRING( (SELECT ',' + Comments.Comment FROM Comments INNER JOIN tasks ON comments.entityid = tasks.taskid FOR XML PATH('')),2,200000) AS Comments,SUM(comments.timespent) AS TimeSpent FROM comments INNER JOIN tasks ON comments.entityid = tasks.taskid WHERE ( comments.entity = 1 ) GROUP BY Tasks.TaskId 创建表并填充数据 CREATE TABLE Tasks ( TaskID NVARCHAR(20) NOT NULL,); CREATE TABLE Comments ( Entity INT NOT NULL,EntityID NVARCHAR(20) NOT NULL,Comment NVARCHAR(50) NOT NULL,TimeSpent INT NOT NULL ); INSERT INTO Tasks VALUES ( '111754' ); INSERT INTO Comments VALUES (1,'111754','C1',4 ),(1,'C2',1 ),'C3',79 ); 执行SQL SELECT Tasks.TaskId,SUM(comments.timespent) AS TimeSpent FROM comments INNER JOIN tasks ON comments.entityid = tasks.taskid WHERE comments.entity = 1 GROUP BY Tasks.TaskId 查看结果. TASKID COMMENTS TIMESPENT 111754 C1,C3 84 (编辑:ASP站长) 【免责声明】本站内容转载自互联网,其相关言论仅代表作者个人观点绝非权威,不代表本站立场。如您发现内容存在版权问题,请提交相关链接至邮箱:bqsm@foxmail.com,我们将及时予以处理。 |
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